+0

# pre cal need help

+1
41
3
+155

help

Nov 12, 2020

#1
+93
+4

Hello Cdortch.

SOLUTION:

Do you know Heron's Formula? It will greatly benefit you in this problem.

Heron's formula states that the area of a triangle is equal to the square root of the semiperimeter times... well, I'll just write it out. $s$ is semiperimeter. $A=\sqrt{s(s-a)(s-b)(s-c).}$ Now, when we plug in the values, we find that the area of a smaller triangle is $\sqrt{\dfrac{9}{2}(\dfrac{9}{2}-1)(\dfrac{9}{2}-4){(\dfrac{9}{2}-4)}}$. We then multiply this by 2.

Putting the above equation into a calculator, we get $\frac{3\sqrt{7}}{2}$.

Hope this helped!

Nov 12, 2020
#2
+112375
+1

Nice, Eternity  !!!!

Nov 12, 2020
#3
+93
+2

Thanks!

ETERNITY  Nov 12, 2020