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avatar+155 

help

 Nov 12, 2020
 #1
avatar+93 
+4

Hello Cdortch.

 

 

SOLUTION:

Do you know Heron's Formula? It will greatly benefit you in this problem.

 

Heron's formula states that the area of a triangle is equal to the square root of the semiperimeter times... well, I'll just write it out. $s$ is semiperimeter. \[A=\sqrt{s(s-a)(s-b)(s-c).}\] Now, when we plug in the values, we find that the area of a smaller triangle is $\sqrt{\dfrac{9}{2}(\dfrac{9}{2}-1)(\dfrac{9}{2}-4){(\dfrac{9}{2}-4)}}$. We then multiply this by 2.

 

Putting the above equation into a calculator, we get $\frac{3\sqrt{7}}{2}$.

 

 

Hope this helped! angel

 Nov 12, 2020
 #2
avatar+112375 
+1

Nice, Eternity  !!!!

 

 

cool cool cool

 Nov 12, 2020
 #3
avatar+93 
+2

Thanks!

ETERNITY  Nov 12, 2020

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