The concentration C(t) of a drug administered to a patient intravenously jumps to its highest level almost immediately. The concentration subsequently decays exponentially according to the law C(t)=C0e^-kt where C0=C(0). The physician adminstering the drug would like to have m

where m is the concentration below which the drug is ineffective and M is the concentration above which the drug is dangerous. The half-life of the drug is

28

hours. Suppose a patient receives

17

milligrams of the drug at

8 AM How much of the drug is in the patient's blood at 4

P.M. the same day?

At 4 PM _____ miligrams of the drug are in the patients blood????????

mharrigan920 Mar 25, 2020

#1**+2 **

C(t) = 17 e^{-kt }I will assume t is hours

1/2 of the drug will be gone 28 hours = 8.5 mg

8.5 mg = 17 e^{-k(28)} yields k = .0247553

8AM to 4 PM is 8 hours = t

17 e^{-.0247553(8)} = 13.95 mg still in pt at 4 pm

ElectricPavlov Mar 25, 2020