+318 The concentration C(t) of a drug administered to a patient intravenously jumps to its highest level almost immediately. The concentration subsequently decays exponentially according to the law C(t)=C0e^-kt where C0=C(0). The physician adminstering the drug would like to have m
where m is the concentration below which the drug is ineffective and M is the concentration above which the drug is dangerous. The half-life of the drug is
28
hours. Suppose a patient receives
17
milligrams of the drug at
8 AM How much of the drug is in the patient's blood at 4
P.M. the same day?
At 4 PM _____ miligrams of the drug are in the patients blood????????
+36915 C(t) = 17 e-kt I will assume t is hours
1/2 of the drug will be gone 28 hours = 8.5 mg
8.5 mg = 17 e-k(28) yields k = .0247553
8AM to 4 PM is 8 hours = t
17 e-.0247553(8) = 13.95 mg still in pt at 4 pm
