Approximate apparent magnitudes of celestial object A is −19
and of celestial object B is
How many times brighter is the celestial object A than celestial object B
One magnitude corresponds to a brightness factor of 2.512 times The more NEGATIVE the BRIGHTER the object is....in this example A is much brighter than B....How much brighter?
3.03 - - 19 = 22.03
22.03 x 2.512 = A is ~55 times brighter than B