First off, I'd like to thank you for reading in advance. The work you do helps so many people and you don't have any idea how appreciative I am for that.
I am in a Pre-Calculus class and I am haing some trouble with vectors. Homework involved a worksheet with a bunch of the same sort of types of questions, just with different numbers, variables, opperations and set ups.
Instructions: "Find the magnitude and direction angle of the resultant vector." We were also asked to draw the vectors.
The first problem gave:
Thank you for any help you provide in advance. It means a lot!
When they give you an x,y magnitudes, you are loking for the resultant HYPOTENUSE of a right triangle....first sketch the x and the y components, then use the pythagorean theorm to find the hypotenuse...
First one x magnitude =6 y magnitude = -10 hypotenuse = sqrt(6^2 + 10^2) = 11.66
the angle will be in the FOURTH quadrant (because y is negative)
and is equal to arctan (-10/6) = -59 degrees
Do you see how it is done? Try the second one!
For the THIRD one.... ADD the x and y's of a and g....do the sketch, then do the math the same way with the results of adding these values ! Easy Peasy ! (once you catch on)