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A motorboat is capable of traveling at a speed of

10

miles per hour in still water. On a particular​ day, it took

10

minutes longer to travel a distance of

4

miles upstream than it took to travel the same distance downstream. What was the rate of current in the stream on that​ day?

 Jun 3, 2020
 #1
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+1

Let v be speed of current.

 

Let t be time to travel 4 miles downstream.

 

time = distance/speed

 

t = 4/(10 + v).    (1)

 

t + (10/60) = 4/(10 - v).    (2)

 

You now have two equations in two unknowns.  Solve them to find v.

 Jun 3, 2020

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