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# Precalc- trig stuff

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Find an algebraic expression for $$tan(arcsin(\frac{\sqrt{36-x^2}}{6}))$$.

I don't understand why the answer has to be simplified from $$\frac{\sqrt{36-x^2}}{\sqrt{x^2}}$$ to $$\frac{\sqrt{36-x^2}}{x}$$ since radical x2 isn't equal to x when x is negative.

Mar 21, 2019

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The derivation of the answer is based on a right triangle with opposite leg equal to x.

Triangles don't have negative length legs.

But you are correct that it should be mentioned that 0<= x <=6

Mar 21, 2019