+545 Pressure varies inversely as volume. When the pressure is 16 pascals, the volume is 84 liters. What would the volume (in liters) be if the pressure is reduce to 12 pascals?
+36915 Here is what you are given: v = k 1/p Where 'k' is a constant
84 = k (1/16) Yields k = 1344
v = 1344 (1/p) Now substitute for the new 'p' v = 1344 (1/12) = 112 liters
ANOTHER way p1/p2 = v2/v1 (they are inverse) p1/p2 x v1 = v2 16/12 x 84 = 112
