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p and q are both prime numbers.

7p+q and pq+11 are prime numbers.

what is the value of (p^2 + q^p)*(q^2 + p^q) ?

 Feb 9, 2019
 #1
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\(\text{well just trying the first two primes, 2 and 3, for p and q we get}\\ 7p+q = 14+3 = 17 \text{ is prime}\\ pq + 11 = 2\cdot 3 + 11 = 6 + 11 = 17 \text{ is also prime}\\ (2^2 + 3^2)(3^2+2^3) = (4+9)(9+8) = 13 \cdot 17 = 221\)

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 Feb 10, 2019

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