p and q are both prime numbers.
7p+q and pq+11 are prime numbers.
what is the value of (p^2 + q^p)*(q^2 + p^q) ?
\(\text{well just trying the first two primes, 2 and 3, for p and q we get}\\ 7p+q = 14+3 = 17 \text{ is prime}\\ pq + 11 = 2\cdot 3 + 11 = 6 + 11 = 17 \text{ is also prime}\\ (2^2 + 3^2)(3^2+2^3) = (4+9)(9+8) = 13 \cdot 17 = 221\)
+160 
