A bag contains 4 balls. Each ball is a single color, and 3 distinct colors are represented in the bag. What is the probability that the first 2 balls selected without replacement are the same color? Express your answer as a common fraction.
It must be that there are 2 of one color and then 1 each of the other two colors.
\(P[\text{we pick the two like colored balls in two choices}]=\dfrac 1 2 \dfrac 1 3 = \dfrac 1 6\)
