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A bag contains 4 balls. Each ball is a single color, and 3 distinct colors are represented in the bag. What is the probability that the first 2 balls selected without replacement are the same color? Express your answer as a common fraction.

Guest Oct 11, 2018

Best Answer 

 #1
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It must be that there are 2 of one color and then 1 each of the other two colors.

 

\(P[\text{we pick the two like colored balls in two choices}]=\dfrac 1 2 \dfrac 1 3 = \dfrac 1 6\)

Rom  Oct 11, 2018
 #1
avatar+3154 
+2
Best Answer

It must be that there are 2 of one color and then 1 each of the other two colors.

 

\(P[\text{we pick the two like colored balls in two choices}]=\dfrac 1 2 \dfrac 1 3 = \dfrac 1 6\)

Rom  Oct 11, 2018

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