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avatar+348 

Hi, so this is a question that I got wrong on my HW and I don't know why or what the correct answer is.

 

Two cards are drawn at random from a deck of 52 cards without replacing the first card before choosing the second card.

What is the probability that the first card is a heart and the second card is a number card that is black?

 

Enter your final answes as reduced fractions.

 

My answer was \(\frac{5}{51}\)

 

My formula set up:

 

\(\frac{13}{52}\times\frac{20}{51}=0.980392157=\frac{5}{51}\)

 

Thank you for all your help in advance!!

 Apr 10, 2021
 #1
avatar+31586 
+3

13 / 52 is correct..... then there are 51 cards left of which  18 are black number cards    ace is not a number   ( not 20)

 Apr 10, 2021
edited by Guest  Apr 10, 2021
edited by ElectricPavlov  Apr 10, 2021
 #2
avatar+118626 
+2

P(first card  is a heart  and second  is  a black "number" card)  =

 

1/4   *   18 / 51   =

 

1/4  *  6 / 17  = 

 

6  / 68   =

 

3 / 34

 

 

cool cool cool

 Apr 10, 2021

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