A student wishes to schedule mathematics, English, statistics, and science. These classes are available every hour between 8 A.M. and noon (4 hours).
(a) How many different schedules are possible?
(b) How many schedules are possible if this student wants to take mathematics at 11 A.M. with her favorite instructor, Mr. Eldridge?
Well there are 4 possibilities for the first hour.
Now one class has been taken, so, how many possibilities are there for the second hour? etc.
What do you think you should do to answer part a ?
if you can do that, then you can also have a shot at part b.
Please allow Bleh674 to respond with an attempt before giving more help.
Hi and thank you for your help, I already know that the answer to part a is 24 I only need help with part b.
Well show me how you did part a? And tell me if you really understand?
Part b is exactly the same idea.
There are 4 choices for the first hour.
one subject is now chosen so there are 3 subjects left.
There are 3 subjects fo the second hour
There are 2 left for the 3rd hour
and only one left for the last hour.
4*3*2*1 = how many possibilities there are
What does 4*3*2*1 equal?
Now forget about formulas and tell me how to do part b.
I apologize, I thought we were supposed to be using the permutation and combination formulas on all of it which is why I got confused. I guess since math would be at 11 you would only have to figure out how many schedules were possible for the other three subjects. Therefore, you would multiply 3,2, and 1 in order to get 6.
Yes that is right and if you want to use formula (which shouls also be your second choice with these.)
It will be P(3,3) becasue you are only worrying aobut ordering 3 subjects.
please understand the logic of these without the forumula.
Then when you do need to use it the formula will make more sense.