+83 What is the probability of rolling a number greater than 4 on a number cube and then spinning an even number on a spinner divided into 12 equal sectors numbered 1 through 12?
(Answer with a simplified fraction please.)
+633 Let's start from the top:
There is a 1/36 chance of rolling a 2
There is a 2/36 chance of rolling a 3
There is a 3/36 chance of rolling a 4
Adding them up, we get 6/36, or 1/6.
Subtracting this from unity (1) we get 5/6.
There is a 1/12 chance of spinning a 2
There is a 1/12 chance of spinning a 4
There is a 1/12 chance of spinning a 6
There is a 1/12 chance of spinning a 8
There is a 1/12 chance of spinning a 10
There is a 1/12 chance of spinning a 12
Adding them up, we get 6/12, or 1/2
Multiplying the numerators and denominators horizontally, we get \(\tfrac{5}{12}\).
Did this help? I hope it did! 
+129852 Assuming that the number cube has the possible outcomes of1,2,3,4,5 or 6.....the probability of rolling a number > 4 = [ 2 favorable outcomes ] / [6 possible outcomes ] = 2/6 = 1/3
And the probability of spinning an even number =
[ 6 favorable outcomes] / [ 12 possible outcomes] =
6/12 = 1/2
So....the probability = P(first event) * P(second event) = (1/3) * (1/2) = 1/6
