What is the probability of rolling a number greater than 4 on a number cube and then spinning an even number on a spinner divided into 12 equal sectors numbered 1 through 12?

(Answer with a simplified fraction please.)

RedBlue
Dec 21, 2017

#1**+1 **

Let's start from the top:

There is a 1/36 chance of rolling a 2

There is a 2/36 chance of rolling a 3

There is a 3/36 chance of rolling a 4

Adding them up, we get 6/36, or 1/6.

Subtracting this from unity (1) we get 5/6.

There is a 1/12 chance of spinning a 2

There is a 1/12 chance of spinning a 4

There is a 1/12 chance of spinning a 6

There is a 1/12 chance of spinning a 8

There is a 1/12 chance of spinning a 10

There is a 1/12 chance of spinning a 12

Adding them up, we get 6/12, or 1/2

Multiplying the numerators and denominators horizontally, we get \(\tfrac{5}{12}\).

Did this help? I hope it did!

helperid1839321
Dec 21, 2017

#3**+1 **

Assuming that the number cube has the possible outcomes of1,2,3,4,5 or 6.....the probability of rolling a number > 4 = [ 2 favorable outcomes ] / [6 possible outcomes ] = 2/6 = 1/3

And the probability of spinning an even number =

[ 6 favorable outcomes] / [ 12 possible outcomes] =

6/12 = 1/2

So....the probability = P(first event) * P(second event) = (1/3) * (1/2) = 1/6

CPhill
Dec 21, 2017