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# Probability problem

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Meyer rolls two fair, ordinary dice with the numbers 1, 2, 3, 4, 5, 6 on their sides. What is the probability that both of the dice shows a square number?

Feb 15, 2022

#1
+1382
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Each roll has a $$1 \over3$$ chance of being a square (1 and 4)

Thus, the probability that both rolls are a square is: $${1 \over 3} \times {1 \over 3} = \color{brown}\boxed{1 \over9}$$

Feb 15, 2022

#1
+1382
+2
Each roll has a $$1 \over3$$ chance of being a square (1 and 4)
Thus, the probability that both rolls are a square is: $${1 \over 3} \times {1 \over 3} = \color{brown}\boxed{1 \over9}$$