Meyer rolls two fair, ordinary dice with the numbers 1, 2, 3, 4, 5, 6 on their sides. What is the probability that both of the dice shows a square number?

Guest Feb 15, 2022

#1**+2 **

Each roll has a \(1 \over3\) chance of being a square (1 and 4)

Thus, the probability that both rolls are a square is: \({1 \over 3} \times {1 \over 3} = \color{brown}\boxed{1 \over9}\)

BuilderBoi Feb 15, 2022

#1**+2 **

Best Answer

Each roll has a \(1 \over3\) chance of being a square (1 and 4)

Thus, the probability that both rolls are a square is: \({1 \over 3} \times {1 \over 3} = \color{brown}\boxed{1 \over9}\)

BuilderBoi Feb 15, 2022