Determine the sum of all values x such that when three dice are rolled, the probability that their sum is equal to x is 1/8.
If I understand your question, then:
1 / 216, This is the chance of rolling a total of 3
1 / 72,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>total of 4
1 / 36,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>5
5 / 108,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>6
5 / 72,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>7
7 / 72,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>8
25 / 216,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>9
1 / 8,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>10
1 / 8,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>11
25 / 216,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>12
7 / 72,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>13
5 / 72,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>14
5 / 108,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>15
1 / 36,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>16
1 / 72,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>17
1 / 216>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> 18
So, the value of x =10 and 11 when the 3 dice have the probability of: 27 / 216 = 1 / 8
