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Determine the sum of all values x such that when three dice are rolled, the probability that their sum is equal to x is 1/8.

 Aug 28, 2020
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If I understand your question, then:

1 / 216,                     This is the chance of rolling a total of  3
1 / 72,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>total of  4 
1 / 36,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>5 
5 / 108,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>6 
5 / 72,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>7
7 / 72,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>8 
25 / 216,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>9 
1 / 8,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>10 
1 / 8,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>11 

25 / 216,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>12 
7 / 72,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>13 
5 / 72,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>14 
5 / 108,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>15 
1 / 36,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>16 
1 / 72,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>17 
1 / 216>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> 18

So, the value of x =10 and 11 when the 3 dice have the probability of: 27 / 216 = 1 / 8

 Aug 28, 2020

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