A board game has two spinners. The first spinner has 4 equal areas labeled 1, 2, 3 and 4. The secondspinner has 3 equal areas that are labeled: Move Ahead, Move Back, and Do Not Move. What is the

probability the first spinner will land on a 2 and the second spinner will NOT land on Move Back?

Guest Mar 8, 2021

#1**+1 **

1/4 chance of landing on 2 times 2/3 chance of missing Move back

1/4 * 2/3 = 2/12 = 1/6

ElectricPavlov Mar 8, 2021