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# probability question

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53
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+550

At a Halloween party, you play a dart game where you win teeth based on where your dart throw lands. The probability of hitting the outer ring is 8% and you win 5 teeth. The probability of hitting the yellow ring is 26% and you win 6 teeth. The probability of hitting the blue ring is 34% and you win 7 teeth. The probability of hitting the orange ring is 20% and you win 9 teeth. The probability of hitting the bullseye is 12% and you win 12 teeth. If you have to pay 8 teeth to throw a dart, what is your mathematical expectation for playing this game? Answer should be in terms of teeth rounded to the hundredths place.

i belive  you have to find the chance of him winning something for each color ring but not sure how to start ;_;

Mar 19, 2021

#1
+117787
+2

Here's  my best attempt

Mathematical expectation =

Winnings * probability of winning -  cost to play

5(.08)  +  6(.26)  + 7(.34)  + 9(.20) + 12(.12)  -  8  =  -21/30  = -0.42  teeth

Mar 20, 2021
#2
+550
+1

thanks!!

xxJenny1213xx  Mar 20, 2021