set up and complete a simulation to find the probability of getting green twice in a row if a spinner is on a circular region that is 1/3 green, 1/6 blue, 1/3 red, and the rest yellow. The spinner is spun twice. Carry out the simulation 30 times and record the outcomes.
+23251 This sounds as if you are actually supposed to do something, not just get a math answer.
Since green = 1/3, blue = 1/6, red = 1/3, and the rest is yellow, first figure out how much is in "the rest".
1/3 + 1/6 + 1/3 = 2/6 + 1/6 + 2/6 = 5/6 ---> This means that yellow also equals 1/6.
To run a simulation, you need something that has 6 possibilities. You can use a calculator that has a "random" feature, or just use a regular die.
If you rolled a die, you could mean a result of either 1 or 2 to be green, 3 to be blue, 4 or 5 to be red, and 6 to be yellow.
Then roll the die 30 times, record the 30 results and turn your answers into greens, blues, reds and yellows.
