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1.

Choose independent or not independent for each scenario.

 

a jar contains twenty coins. Two coins are picked randomly without replacement

A coin is flipped three times

A bag contains 5 red balls and 3 green balls. A red ball is chosen followed by a green ball without replacement.

A spinner contains 3 equal sectors labeled A, B and C. The spinner is spun twice

 

2.

Emma, Sutton, Damaris, Ila and Alice run on the same cross country team. Two of these runners are randomly selected to represent the team at a county meet.

What is the probability that Alice is chosen first and Emma is chosen second?

1/20

1/25

2/9

1/10

 

3.

John rolls a six-sided number cube twice.

What is the probability of getting an even number and then an odd number?

5/6

1/6

1/4

1/2

 

 

Thanks!

 Apr 22, 2019
 #1
avatar+104899 
+1

1.

Choose independent or not independent for each scenario.

 

a jar contains twenty coins. Two coins are picked randomly without replacement  .....any time we have "without replacement,"....the situation is usually dependent

 

A coin is flipped three times -  independent.....no outcone affects any other

 

 

A bag contains 5 red balls and 3 green balls. A red ball is chosen followed by a green ball without replacement.  - dependent

 

A spinner contains 3 equal sectors labeled A, B and C. The spinner is spun twice......independent.....no outcome affects  any other

 

 

cool cool cool

 Apr 22, 2019
 #2
avatar+104899 
+1

2.

Emma, Sutton, Damaris, Ila and Alice run on the same cross country team. Two of these runners are randomly selected to represent the team at a county meet.

What is the probability that Alice is chosen first and Emma is chosen second?

1/20

1/25

2/9

1/10

 

 

Probabilty that  Alice is chosen first  = 1/5

Probability that Emma is chosen seond  = 1/4

So...(1/5) (1/4)  =  1/20

 

 

 

cool cool cool

 Apr 22, 2019
 #3
avatar+104899 
+1

3.

John rolls a six-sided number cube twice.

What is the probability of getting an even number and then an odd number

 

P(even on first roll)  =  3/6

Prob of odd on second roll  = 3/6

So....combined probability  =  (3/6)(3/6)  =  (1/2) (1/2)  =  1/4

 

Note that this is an idependent event.....one roll does not affect any other outcomes

cool cool cool

 Apr 22, 2019

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