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In a bag of three marbles, there are exactly two blue marbles. If Kia randomly chooses two marbles without replacement, the probability of choosing the two blue marbles is one-third. However, before Kia chooses her two marbles, additional marbles are added to the bag. The probability of picking two blue marbles without replacement is still one-third. What is the least number of marbles that could be in the bag after the additional marbles have been added?

 May 31, 2020
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its 10 by solving the equation \(\frac{b}{t}\cdot\frac{b-1}{t-1}=\frac{1}{3}\)

 Jan 9, 2021

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