Probability

Question

0

1387

2

You have been assigned a 9-digit identification number. How many identification numbers are possible?

Guest Feb 26, 2016

+5265

+5

Best Answer

Since there are TEN numbers in between and including 0 and 9, do 10^9.

10^9 = 1000000000, so there are 1 billion different numbers.

rarinstraw1195 · Answer 1 · 2016-02-26T01:25:18

Since there are TEN numbers in between and including 0 and 9, do 10^9.

10^9 = 1000000000, so there are 1 billion different numbers.

CPhill · Answer 2 · 2016-02-26T01:51:55

Rarinstraw is exactly correct.

Asuuming that 0 can be used [ even the number, 000000000]. we have 10 number choices for each position....so.......

(10) (10) (10)......(10)(10), nine times = one billion possibilties !!!