Amaya and Bo each roll a fair, ordinary six-sided die with the numbers 1,2,3,4,5,6 on the sides. What is the probability that Amaya rolls a number at least two than Bo? Enter your answer as a fraction in simplified form.
+2668 There are a total of \(36\) possibilities (\(6\) for the first, \(6\) for the second). The only way the two numbers will be different is if they are the same, or if they differ by one.
There are \(6\) possible ways to roll the same number twice, and there is \(10\) ways to roll two numbers that differ by one.
This means that the probability is \(\color{brown}\boxed {5\over 9}\)
