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Without looking at the labels, Adrien placed four CDs in four cases. What is the probability that exactly one of the CDs is in the wrong case? Express your answer as a common fraction.

 Dec 28, 2020
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This can't happen.....

 

If one CD is in the wrong case, then there must be (at least) two CDs in the the  wrong case

 

For example.....if the  correct CDs  are in cases "3" and  "4",  but CD "1" is in case "2"....then CD "2"  must be in case "1"...so....two CDs are in the wrong cases

 

 

cool cool cool

 Dec 28, 2020

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