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A bag of jelly beans contains 10 red, 6 green, 7 yellow, and 5 orange jelly beans.  

 

a) What is the probability of selecting a red jelly bean, replacing it, and then selecting an orange jelly bean?

b) What is the probability of selecting a green, then yellow, then green jelly bean if you eat them instead of putting them back?

Whiz333  Jun 14, 2017
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A bag of jelly beans contains 10 red, 6 green, 7 yellow, and 5 orange jelly beans.  

 

a) What is the probability of selecting a red jelly bean, replacing it, and then selecting an orange jelly bean?

b) What is the probability of selecting a green, then yellow, then green jelly bean if you eat them instead of putting them back?

 
a) 10+6+7+5 = 28 jelly beans altogether.

10/28 =35.71% probability of selecting a red jelly.

5/28 =17.86% probability of selecting an orange jelly.

 

b) 6/28 =21.43% probability of a green jelly.

7/27 =25.93% probability of a yellow jelly.

6/26 =23.08% probability of a green jelly.

Guest Jun 14, 2017

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