4 fair dice are tossed. If the numbers appearing on the top of the dice are different, find the probability that there is at least 3 of the same parity.
Probability = (1111, 1112, 1113, 1114, 1115, 1116, 1121, 1131, 1141, 1151, 1161, 1211, 1311, 1411, 1511, 1611, 2111, 3111, 4111, 5111, 6111)>Total = 21 * 6 = 126 / 6^4 =7 / 72
