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In a bag, there are: 6 red marbles, 3 blue marbles, 4 yellow marbles, and 1 green marble. Without putting marbles back in the bag:

 

a) What’s the probability of picking 3 red marbles?
b) What’s the probability of picking 2 green marbles?
c) What’s the probability of getting a blue marble first, and then a yellow marble?
d) What’s the probability of picking 1 red marble and 1 blue marble in any order?

 Mar 11, 2021
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Total no. of marbles = 6 + 3 + 4 + 1

                                = 14

a) P(3 red) = \({6 \over 14} * {5 \over 13} * {4 \over 12}\)

                  = 0.06

 

b) P(2 green) = 0 

 

c) P(blue then yellow) = \({6 \over 14}*{4 \over 13}\)

                                    = 0.13

 

d) P(1 red, 1 blue) = \(({6 \over 14}*{3 \over 13}) + ({3 \over 14}*{6 \over 13})\)

                              = \({36 \over 182}\)

                              = 0.2

 Mar 11, 2021

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