In a bag, there are: 6 red marbles, 3 blue marbles, 4 yellow marbles, and 1 green marble. Without putting marbles back in the bag:
a) What’s the probability of picking 3 red marbles?
b) What’s the probability of picking 2 green marbles?
c) What’s the probability of getting a blue marble first, and then a yellow marble?
d) What’s the probability of picking 1 red marble and 1 blue marble in any order?
+526 Total no. of marbles = 6 + 3 + 4 + 1
= 14
a) P(3 red) = \({6 \over 14} * {5 \over 13} * {4 \over 12}\)
= 0.06
b) P(2 green) = 0
c) P(blue then yellow) = \({6 \over 14}*{4 \over 13}\)
= 0.13
d) P(1 red, 1 blue) = \(({6 \over 14}*{3 \over 13}) + ({3 \over 14}*{6 \over 13})\)
= \({36 \over 182}\)
= 0.2
