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Meyer rolls two fair, ordinary dice with the numbers 1, 2, 3, 4, 5, 6 on their sides. What is the probability that both of the dice shows a square number?

 Jul 14, 2021
 #1
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Possible rolls

1 + 1    =  2

4 + 4  =   8

 

We  have  36 possible outcomes

 

P(2)  =    1/36

P(8)  =    5/36

 

Total Probability =   1/36  + 5/36     =  6/36   =   1/6

 

cool cool cool

 Jul 14, 2021
 #2
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Chris, I believe that one of us has misread the question:  

What is the probability that both of the dice shows a square number?  

 

I could multiply the probabilities, but I believe a visual would be more explanatory to the OP guest.  

 

Here are the possible rolls, with the rolls that solve the problem highlighted.  

 

1,1   1,2   1,3   1,4   1,5   1,6  

2,1   2,2   2,3   2,4   2,5   2,6  

3,1   3,2   3,3   3,4   3,5   3,6  

4,1   4,2   4,3   4,4   4,5   4,6  

5,1   5,2   5,3   5,4   5,5   5,6  

6,1   6,2   6,3   6,4   6,5   6,6

 

The probability is shown to be 4/36 = 1/9.

Guest Jul 15, 2021
 #3
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Ah, yes.....I see my mistake....I read it as  the  "same square".....thanks for the correction  !!!!

 

 

cool cool cool

CPhill  Jul 15, 2021

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