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Phillip flips an unfair coin eight times. This coin is twice as likely to come up heads as tails. How many times as likely is Phillip to get exactly three heads than exactly two heads?

Jz1234  Aug 27, 2017
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P (three heads) =  C(8,3)(2/3)^3(1/3)^5  = 448 / 6561

 

P (two heads) = C(8,2)(2/3)^2(1/3)^6  = 112 / 6561

 

So......     448 / 112   =  4 times more likely to get 3 heads than 2 heads

 

 

 

cool cool cool

CPhill  Aug 27, 2017

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