Phillip flips an unfair coin eight times. This coin is twice as likely to come up heads as tails. How many times as likely is Phillip to get exactly three heads than exactly two heads?
P (three heads) = C(8,3)(2/3)^3(1/3)^5 = 448 / 6561
P (two heads) = C(8,2)(2/3)^2(1/3)^6 = 112 / 6561
So...... 448 / 112 = 4 times more likely to get 3 heads than 2 heads
+50 
