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3 cards are chosen at random from a standard 52-card deck. What is the probability that they can be arranged into a group of three consecutive cards, all of the same suit? For this problem, an Ace can either come before a 2 or after a King, but not both (so A23 and QKA both count, but KA2 doesn't).

 

Please help me with this I'm not sure why A23 and QKA count by KA2 doesn't.

 Aug 22, 2021
 #1
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The probability is 4*C(13,3)/C(52,3) = 22/425.

 Aug 22, 2021
 #2
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Thats incorrect.

Note that the cards have to be consecutive. so u can't just randomly choose 3 cards

Guest Aug 22, 2021

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