Two distinct numbers are selected simultaneously and at random from the set \(\{1, 2, 3, 4\}\) What is the probability that the smaller one divides the larger one? Express your answer as a common fraction.

Guest Feb 6, 2022

#1**+1 **

There are a total of 4 choose 2 = 6 pairs that can be chosen. This number is small enough to go through each pair one by one.

(1, 2), (1, 3), (1, 4): one divides into every number, so all of these work

(2, 3): 2 does not divide evenly into 3

(2, 4): 2 divides evenly into 4

(3, 4): 3 does not divide evenly into 4

This gives 4 pairs that work for an overall probability of 4/6 = **2/3.**

CubeyThePenguin Feb 6, 2022