We flip a fair coin 10 times. What is the probability that we get heads in at least 8 of the 10 flips?
+67 P (Heads ≥ 8 flips) = P( Tails ≤ 2 flips ) =
C(10,0)(1/2)^10 + C(10,1) (1/2)^10 + C(10,2)(1/2)^10 = 7 / 128
Techno the p*g.
+67 P (Heads ≥ 8 flips) = P( Tails ≤ 2 flips ) =
C(10,0)(1/2)^10 + C(10,1) (1/2)^10 + C(10,2)(1/2)^10 = 7 / 128
Techno the p*g.
