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We flip a fair coin 10 times. What is the probability that we get heads in at least 8 of the 10 flips?

 Jun 16, 2021

Best Answer 

 #1
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P (Heads  ≥ 8 flips)  =  P( Tails ≤ 2 flips )  =

 

C(10,0)(1/2)^10   + C(10,1) (1/2)^10  + C(10,2)(1/2)^10  =  7 / 128
 

Techno the p*g.

 Jun 16, 2021
 #1
avatar+67 
+1
Best Answer

P (Heads  ≥ 8 flips)  =  P( Tails ≤ 2 flips )  =

 

C(10,0)(1/2)^10   + C(10,1) (1/2)^10  + C(10,2)(1/2)^10  =  7 / 128
 

Techno the p*g.

Technoblade Jun 16, 2021

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