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Right triangle XYZ has legs of length XY = 12 and YZ = 6. Point D is chosen at random within the triangle XYZ. What is the probability that the area of triangle XYD is at most 20?
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Right triangle XYZ has legs of length XY = 12 and YZ = 6. Point D is chosen at random within the triangle XYZ. What is the probability that the area of triangle XYD is at most 20?
If point D is anywhere in the region XYAC then the area of XYD will be at most 20. Can you work out why?
So the prob that XYD<=20 is Area of XYAD divided by Area of XYZ
