Meyer rolls two fair, ordinary dice with the numbers $1,2,3,4,5,6$ on their sides. What is the probability that both dice show a square number?
+23245 Of the numbers: 1, 2, 3, 4, 5, 6, the two square numbers are 1 and 4
The probability that the first die shows a square number is 2 / 6.
The probability that the second die shows a square number is also 2 / 6.
The probability that both show a square number is (2/6) x (2/ 6) =
Even though there are 2 dice, but they are tossed ONCE simultabeously as follows:
(1, 1) , (1, 2) , (1, 3) , (1, 4) , (1, 5) , (1, 6) , (2, 1) , (2, 2) , (2, 3) , (2, 4) , (2, 5) , (2, 6) , (3, 1) , (3, 2) , (3, 3) , (3, 4) , (3, 5) , (3, 6) , (4, 1) , (4, 2) , (4, 3) , (4, 4) , (4, 5) , (4, 6) , (5, 1) , (5, 2) , (5, 3) , (5, 4) , (5, 5) , (5, 6) , (6, 1) , (6, 2) , (6, 3) , (6, 4) , (6, 5) , (6, 6) , Total == 36
Therefore, there are only 2 possibilities of tossing 2 squares: (1, 4) and (4,1): The probability is 2 / 36 ==1/18
