Amaya and Bo each roll a fair, ordinary six-sided die with the numbers 1,2,3,4,5,6 on the sides. What is the probability that Amaya rolls a number at least two than Bo? Enter your answer as a fraction in simplified form.
Amaya and Bo each roll a fair, ordinary six-sided die with the numbers 1,2,3,4,5,6 on the sides. What is the probability that Amaya rolls a number at least two than Bo? Enter your answer as a fraction in simplified form.
Did you mean at least two times that of Bo's?
Here are all of the possible combinations.
Let's say Amaya's die is on the left.
1,1 1,2 1,3 1,4 1,5 1,6
2,1 2,2 2,3 2,4 2,5 2,6
3,1 3,2 3,3 3,4 3,5 3,6
4,1 4,2 4,3 4,4 4,5 4,6
5,1 5,2 5,3 5,4 5,5 5,6
6,1 6,2 6,3 6,4 6,5 6,6
I count 9 that meet the criterion. So the likelihood is 9/36 which reduces to 1/4.
If instead you meant to say two more than Bo's, then you can count those and divide the total by 36.
