Probability

Solution:

$\text {A quick method for solving is to note that all fours (4) are even and }\\ \text { cannot be independent of even, so the probability is } \dfrac {6}{13} = .4615 \\ \text { }\\ \text {Formally: }\\ \large \mathbb \rho \small (4 \text { or even}) = \large \mathbb \rho \small (4) + \large \mathbb \rho \small (\text {even}) - \large \mathbb \rho \small (4 \text { and even})\\ = \dfrac{4}{52} + \dfrac {24}{52} - \left( \dfrac {4}{52} * 1 \right) = \mathbf {46.15} \%\\ $

GA

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