Marvin roll a die. If he obtain a 5, he chooses a banana from box 1 where 4 are green and 6 are yellow. If he obtain a number that is not a 5, he chooses a banana from box 2 where 8 bananas are green and 3 bananas are yellow. What is the probability of obtaining a colored green banana?
+33615 Marvin roll a die. If he obtain a 5, he chooses a banana from box 1 where 4 are green and 6 are yellow. If he obtain a number that is not a 5, he chooses a banana from box 2 where 8 bananas are green and 3 bananas are yellow. What is the probability of obtaining a colored green banana?
P(green banana) = (1/6)*(4/10) + (5/6)*(8/11)
I'll leave you to simplify the numbers.
