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Marvin roll a die. If he obtain a 5, he chooses a banana from box 1 where 4 are green and 6 are yellow. If he obtain a number that is not a 5, he chooses a banana from box 2 where 8 bananas are green and 3 bananas are yellow. What is the probability of obtaining a colored green banana?

 May 29, 2020
 #1
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Marvin roll a die. If he obtain a 5, he chooses a banana from box 1 where 4 are green and 6 are yellow. If he obtain a number that is not a 5, he chooses a banana from box 2 where 8 bananas are green and 3 bananas are yellow. What is the probability of obtaining a colored green banana?

 

P(green banana) = (1/6)*(4/10) + (5/6)*(8/11) 

 

I'll leave you to simplify the numbers.

 May 29, 2020

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