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A box contains 5 black marbles, 3 red marbles, 3 yellow marbles, and 1 green marble. What is the probability of drawing three marbles of the following colors, in order, if they are drawn without replacement: black, green, black?

 Feb 11, 2016
 #1
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This is what I still remember:

 

5c1*1c1*4c1/12c3

 

12 is the sum of the marbles

 Feb 11, 2016
 #2
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5 over 12 x 1 over 11 x 4 over 10= 1 OVER 66 (1/66)

 Feb 11, 2016
 #3
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the probability to draw:

black marble: 5/12

green: 1/12

 

black,green,black512×112(1) because you draw one marble)×5(1) because you draw one black marble)12(2) because you draw two marbles)(5/12)(1/11)(4/10)=1/66

 Feb 11, 2016
edited by Solveit  Feb 11, 2016

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