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Six 6-sided dice are rolled. What is the probability that three of the dice show prime numbers and the rest show non-prime numbers?

 Dec 8, 2020
 #1
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Im not too good at probability, but there is a 3/6 chance of it being a prime number (2,3,5) so that would be (3/6)^3 chance of the first 3 being prime, and then a (3/6)^3 for it not to be a prime number. so that would be (3/6)^6

 Dec 8, 2020
 #2
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Primes are  2,3 and  5 =    1/2  chance of showing a prime

Nonprimes are  1, 4, 6 =  1/2  chance of showing a non-prime

 

P (that three show primes )  =  C(6,3)  ( 1/2)^3  ( 1/2)^3    =  20  * (1/8)^2  =  20/64  =  5/16

 

cool cool cool

 Dec 8, 2020

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