A bag contains 4 blue discs and 2 red discs. A disc is chosen at random from the bag and not returned. A second disc is then chosen from the bag.

Find the probability that The first disc is red and the second disc is blue

One disc is blue and the orther disc is red in any order

Guest Apr 10, 2019

#1**0 **

First disc red 2 out of 6 chance 2/6 The disc is not returned , so there is only 5 left in the bag:

Second disc blue 4 out of 5 chance 4/5

2/6 * 4/5 = 8/30 = 4/15

Not positive about the second part but there are only 2 possibilities red blue (which we already calc'd above ) and blue red

First blue 4/6

Second red 2/5 4/6 * 2/5 = 8/30 = 4/15

added to the first result 4/15 + 4/15 = 8/15 for any order

ElectricPavlov Apr 10, 2019