A stick is broken at two points, chosen at random. If the length of the stick is 6 then what is the probability that all three resulting pieces are shorter than 2 units?

Guest Mar 15, 2023

#1**0 **

Let the stick be a line segment of length 6, and let X and Y be the points where the stick is broken, chosen at random. We want to find the probability that all three resulting pieces are shorter than 2 units.

First, we can assume without loss of generality that X < Y. Then the three pieces have lengths X, Y-X, and 6-Y.

For all three pieces to be shorter than 2 units, we need:

- X < 2

- Y - X < 2

- 6 - Y < 2

Simplifying these inequalities, we get:

- X < 2

- Y < X + 2

- Y > 4

We can visualize these inequalities in the following region:

```

Y

|\

| \

| \

| \

______|____\______ X

0 6

```

The region above represents all possible pairs of X and Y that result in three pieces shorter than 2 units. The horizontal axis represents the position of X, and the vertical axis represents the position of Y.

The shaded triangle in the region represents the pairs of X and Y that satisfy the three inequalities above. This is a right triangle with base 4 and height 2, so its area is:

(1/2) * 4 * 2 = 4

The total area of the region above is (1/2) * 6 * 6 = 18. So the probability that all three resulting pieces are shorter than 2 units is:

P(X, Y satisfy the inequalities) = Area of the shaded triangle / Total area of the region

= 4 / 18

= 2 / 9

Therefore, the probability that all three resulting pieces are shorter than 2 units is 2/9.

Justingavriel1233 Mar 16, 2023