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When rolling two standard cubes (6-sided die), what is the probability that you roll sum of 11? Convert your answer to decimal form, then round to 3 decimal places

 Sep 11, 2021
 #1
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Explanation:

 

There are 36 possible outcomes in rolling two six-sided cubes.

 

Of those 36 possibilities, five of them result in a sum of 6.

 

1+5:   2+4:   3+3:   4+2:   5+1

 

(1+5) is different from (5+1) use two different colors of dice such as black and white to make this obvious)

 

5 = the number of possibilities of getting a six.


36 = the total number of possibilities (6×6=36)

 

So the probability is 5/36

 Sep 11, 2021
edited by weredumbmaster22  Sep 11, 2021
 #3
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Are we looking at the same problem?  The problem I'm looking at says "roll sum of 11" not sum of 6.   

Guest Sep 12, 2021
 #2
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When rolling two standard cubes (6-sided die), what is the probability that you roll sum of 11? Convert your answer to decimal form, then round to 3 decimal places    

 

Here are all the possible rolls.  

 

1,1   1,2   1,3   1,4   1,5   1,6  

2,1   2,2   2,3   2,4   2,5   2,6  

3,1   3,2   3,3   3,4   3,5   3,6  

4,1   4,2   4,3   4,4   4,5   4,6  

5,1   5,2   5,3   5,4   5,5   5,6  

6,1   6,2   6,3   6,4   6,5   6,6

 

How many ways to total 11 ....  count them, there are 2  

How many possible rolls ........  count them, there are 36  

 

The likelihood of rolling an 11 is 2 out of 36, or in decimal form to three places, 0.056    

.

 Sep 12, 2021

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