What is the probability that at least two of the faces match when you roll four fair six-sided dice? Express your answer as a common fraction.
First die, any number==6/6
2nd die, probability that it is different fron the first==5/6
3rd die, probability that it is different from the first two ==4/6
4th die, probability that it is different from the first three ==3/6
Then, the overall probability that they are all different from each other==6/6 x 5/6 x 4/6 x 3/6==360 / 6^4
Therefore, the probability that at least 2 of them are the same==1 - [360 /1,296] ==13 /18 ==72.22%
