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There are 10 different billiard balls are there, how many ways of choosing them by 2 are there so that when you take it you don't put it back?

 Nov 9, 2021
 #1
avatar+115420 
+2

Hi Solveit  laugh

 

o you mean:

There are 10 billiard balls

One is taken and not returned.

Then a second one is taken.

How many ways can the two be taken?

 

 

there are 10 ways that the first one can be taken and then 9 ways the second one can be taken so that is 

10*9 = 90 ways

 

Note: If order does not matter then you will have to divide this by 2 and get  45 ways.

 Nov 9, 2021
edited by Melody  Nov 9, 2021
 #2
avatar+2578 
+1

it is like picking and then removing from the deck. So, the second one is also not being put back.

Solveit  Nov 10, 2021
 #3
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0

Yes. that is what I assumed  laugh

Melody  Nov 10, 2021

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