A coin bank contains nickels, dimes, and quarters totaling $\$5.45$. Ifthere are twice as many quarters as dimes and 11 more nickels than quarters, how many of each coin are in the bank?
q = quarters
d = dimes = 1/2 q
n = nickels = q+11
25 q + 10(1/2q) + 5 (q+11) = 545 solve for q
then d = 1/2 q and n = q+11