+33616 $$$$\frac{c}{\sqrt{2x}}+\frac{y}{2\sqrt{x}}$$\\
Multiply top and bottom of 1st term by $\sqrt2$\\
$$\frac{c}{\sqrt{2x}}+\frac{y}{2\sqrt{x}}=\frac{\sqrt2c}{\sqrt2\sqrt{2x}}+\frac{y}{2\sqrt{x}}$$\\
The denominator of the first term can be rewritten as $\sqrt2\sqrt{2x}=2\sqrt{x}$ so
$$ \frac{c}{\sqrt{2x}}+\frac{y}{2\sqrt{x}}=\frac{\sqrt2c}{2\sqrt{x}}+\frac{y}{2\sqrt{x}}$$\\
Both terms now have a common denominator so:
$$\frac{c}{\sqrt{2x}}+\frac{y}{2\sqrt{x}}=\frac{\sqrt2c+y}{2\sqrt{x}}$$
+33616 $$$$\frac{c}{\sqrt{2x}}+\frac{y}{2\sqrt{x}}$$\\
Multiply top and bottom of 1st term by $\sqrt2$\\
$$\frac{c}{\sqrt{2x}}+\frac{y}{2\sqrt{x}}=\frac{\sqrt2c}{\sqrt2\sqrt{2x}}+\frac{y}{2\sqrt{x}}$$\\
The denominator of the first term can be rewritten as $\sqrt2\sqrt{2x}=2\sqrt{x}$ so
$$ \frac{c}{\sqrt{2x}}+\frac{y}{2\sqrt{x}}=\frac{\sqrt2c}{2\sqrt{x}}+\frac{y}{2\sqrt{x}}$$\\
Both terms now have a common denominator so:
$$\frac{c}{\sqrt{2x}}+\frac{y}{2\sqrt{x}}=\frac{\sqrt2c+y}{2\sqrt{x}}$$
