\frac{c}{\sqrt{2x}}+\frac{y}{2\sqrt{x}}Multiplytopandbottomof1sttermby$√2$\frac{c}{\sqrt{2x}}+\frac{y}{2\sqrt{x}}=\frac{\sqrt2c}{\sqrt2\sqrt{2x}}+\frac{y}{2\sqrt{x}}Thedenominatorofthefirsttermcanberewrittenas$√2√2x=2√x$so \frac{c}{\sqrt{2x}}+\frac{y}{2\sqrt{x}}=\frac{\sqrt2c}{2\sqrt{x}}+\frac{y}{2\sqrt{x}}Bothtermsnowhaveacommondenominatorso:\frac{c}{\sqrt{2x}}+\frac{y}{2\sqrt{x}}=\frac{\sqrt2c+y}{2\sqrt{x}}$$
.\frac{c}{\sqrt{2x}}+\frac{y}{2\sqrt{x}}Multiplytopandbottomof1sttermby$√2$\frac{c}{\sqrt{2x}}+\frac{y}{2\sqrt{x}}=\frac{\sqrt2c}{\sqrt2\sqrt{2x}}+\frac{y}{2\sqrt{x}}Thedenominatorofthefirsttermcanberewrittenas$√2√2x=2√x$so \frac{c}{\sqrt{2x}}+\frac{y}{2\sqrt{x}}=\frac{\sqrt2c}{2\sqrt{x}}+\frac{y}{2\sqrt{x}}Bothtermsnowhaveacommondenominatorso:\frac{c}{\sqrt{2x}}+\frac{y}{2\sqrt{x}}=\frac{\sqrt2c+y}{2\sqrt{x}}$$