problem with denominator

\frac{c}{\sqrt{2x}}+\frac{y}{2\sqrt{x}} $$\\ Multiply top and bottom of 1st term by $\sqrt2$\\ $$ \frac{c}{\sqrt{2x}}+\frac{y}{2\sqrt{x}}=\frac{\sqrt2c}{\sqrt2\sqrt{2x}}+\frac{y}{2\sqrt{x}} $$\\ The denominator of the first term can be rewritten as $\sqrt2\sqrt{2x}=2\sqrt{x}$ so$$ \frac{c}{\sqrt{2x}}+\frac{y}{2\sqrt{x}}=\frac{\sqrt2c}{2\sqrt{x}}+\frac{y}{2\sqrt{x}} $$\\ Both terms now have a common denominator so:$$ \frac{c}{\sqrt{2x}}+\frac{y}{2\sqrt{x}}=\frac{\sqrt2c+y}{2\sqrt{x}}$$

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