Catherine rolls a -sided die five times, and the product of her rolls is \(1200\). How many different sequences of rolls could there have been? (The order of the rolls matters.)
1200 = 4 * 3 * 2^2 * 5^2 = 2^4 * 3 * 5^2 = 2 2 2 2 3 5 5
Possible rolls
3 4 4 5 5 = 5! / ( 2! * 2!) = 30 sequences
2 4 6 5 5 = 5! / 2! = 60 sequences
If I got them all.....90 sequences
+102 
