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Catherine rolls a -sided die five times, and the product of her rolls is \(1200\). How many different sequences of rolls could there have been? (The order of the rolls matters.)

 Feb 9, 2021
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1200  =   4 * 3 * 2^2  * 5^2  =   2^4 * 3 * 5^2  =    2 2 2 2 3 5 5

 

Possible rolls

 

3  4  4   5  5  =    5!  / ( 2! * 2!)  =   30 sequences

2  4  6   5  5  =    5!  / 2!  =    60 sequences 

 

If I got them all.....90  sequences

 

 

cool cool cool 

 Feb 9, 2021
edited by CPhill  Feb 9, 2021
edited by CPhill  Feb 9, 2021

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