In triangle ABC, point P is on side BC such that PA = 13, PB = 14, PC = 4, and the circumcircles of triangles APB and APC have the same radius. Find the area of triangle ABC.
Deleted...
I wrote that answer... Anyway, this question was not answered there, sooooo...
Now I have to repost it because mods are probably gonna lock this thread since there is an "answer" already.
The answer was 108
Did your answer come with a solution?
If so, you might want to explain it to both Melody and I here.
Thanks!
Will do!
