+0  
 
0
455
2
avatar

I've been trying for an hour, but don't know how to solve an equation like this: 3*sqrt(3*x+1)=2*sqrt(x-8). Could someone show me how?

 Oct 4, 2016
 #1
avatar
0

3*sqrt(3*x+1) = 2*sqrt(x-8)  //square each side.

9*(3*x+1) = 4*(x-8)  //Multiply

27x+9 = 4x-32  //subtract 9 from each side

27x = 4x-41  //subtract 4x from each side

27x-4x = -41  //simplify

23x = -41  //divide each side by 23

x = -41/23

 

To prove this, just plug in your x into the original problem.

 Oct 4, 2016
 #2
avatar
0

There are no real solutions. The two curves y = 3sqrt(3x+1) and y = 2sqrt(x-8) do not intersect.

Substituting x = -41/23 as  suggested by the previous answer gets you the square root of a negative quantity.

 Oct 5, 2016

0 Online Users