+0  
 
0
59
4
avatar+703 

Only B please

so far i tried subbing in r for Un but i have no idea how to do it 

please show your step thank you

 Jan 10, 2019
 #1
avatar+27476 
+3

Solution for part b:

 

.

 Jan 10, 2019
 #2
avatar+703 
0

thank you for the detailed explanation

can you explain why you did Ur + U n+1 at the first part of ii please its the only part i didnt catch on to

YEEEEEET  Jan 10, 2019
edited by YEEEEEET  Jan 10, 2019
 #3
avatar+27476 
+2

"can you explain why you did Ur + U n+1 at the first part of ii please "

 

Think of the summation as follows:  \(\sum_{k=1}^nu_k=u_1+u_2+...+u_n\)

 

Hence \(\sum_{k=1}^{n+1}u_k=u_1+u_2+...+u_n+u_{n+1}\)  which is \(\sum_{k=1}^{n+1}u_k=\sum_{k=1}^nu_k+u_{n+1}\)

 

Hope that makes it clear.

Alan  Jan 10, 2019
 #4
avatar+703 
0

perfect! i forgot about that haha thank you

YEEEEEET  Jan 10, 2019

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