Now we all know that 1 multiplied by 1 is always 1... right? Anyway, here's the proof:
Let \({2}^{\sqrt{2}} = x\)
Squaring both sides... \({({2}^{\sqrt{2}})}^{2} = {x}^{2}\)
...we get \(2^2 = {x}^2\)
Get the square root of both sides and... \(2 = x\)
Substituting x, we get \(2^{\sqrt{2}} = 2\)
Since any number raised to 1 is itself, then \(2^{\sqrt{2}} = 2^1\)
Therefore, we get \(\sqrt{2} = 1\)
Enough? Nooooooo. Squaring both sides... \({\sqrt{2}}^2 = 1^2\)
...we get \(2 = 1^2\)
Expanding exponents, you get \(2 = 1*1\)
There you have it. My math teacher used to say that I would do well in collage because of stuff like this... Anyway, now I ask everyone out there who's good at math: help prove it wrong!