Prove that 53n+1 is divisible by 3n+1 for all nonnegative integers n.
Please show all your work.
Just use LTE lemma.
Thanks for responding. I don't know what that is or how to use it. Is there another way to do it?
Hint:53k+1+1=(53k)3+1=(53k+1)(52⋅3k−53k+1)